Since intensity band, as well phase band, is a virtual band computed from i and q bands, why do they have the same values for the intensity band and different values for the phase band?
By the way that doesn’t happen if I compute each interferogram separately (by not using the stack approach).
Is it a bug or does it have an explanation?
PS: I already tried that with more images (e.g. a stack of about 45 interferograms) and all intensity bands are equal.
I’m using latest version of SNAP.
when I do PS phase analysis in StaMPS using interferograms after TopoPhaseRemoval, I found that all differential phase values are quitely close on selected PSs, and the range of deformation rate is very small, any body have idea about this ? thx!
Yes. It is the equation that we can found in the literature.
As is written in equation (27) of your thesis the amplitude becomes the product between the amplitudes of master and slave images.
Since each interferogram in the stack has a different image as slave we should get a different intensity image for each interferogram.
That happens after the interferogram computation and after the deburst but when I remove the topographic phase contribution all the intensity bands in the stack become equal to each other.
And that doesn’t happen when I compute each interferogram separately (by not using the stacking approach).
So I think that maybe the TopoPhaseRemoval operator is not working properly when a stack of interferograms is used as input.