How is velocity (mm/yr) calculated?

[SimoneA]

Dear all,

I hope you can address this question as I cannot really find a solution.

When exporting the data using “v-do” (STaMPS processing) we get LOS velocities in mm/yr at each PS.
Now, how is the velocity value calculated?

Let’s take the following data obtained from a single PS:

|velocity|-1.94938|
|---|---|
|DATE|LOS_Deformation|
|14/05/2003|4.008021|
|27/08/2003|9.077142|
|01/10/2003|1.093995|
|10/12/2003|-29.40341|
|14/01/2004|-12.28669|
|18/02/2004|-5.616016|
|28/04/2004|15.73889|
|02/06/2004|-14.05992|
|07/07/2004|-0.588257|
|15/09/2004|-7.482013|
|20/10/2004|-8.375225|
|24/11/2004|-9.323878|
|29/12/2004|-8.32181|
|02/02/2005|-8.242818|
|13/04/2005|-22.33108|
|18/05/2005|MASTER_DATE|
|22/06/2005|-10.13263|
|27/07/2005|-5.488424|
|31/08/2005|-16.93153|
|05/10/2005|-8.705544|
|09/11/2005|-8.705056|
|14/12/2005|-28.10892|
|18/01/2006|-20.30912|
|29/03/2006|-12.04681|
|03/05/2006|-8.631234|
|07/06/2006|0.1196673|
|16/08/2006|5.558228|
|25/10/2006|-7.099396|
|07/02/2007|-10.37125|
|14/03/2007|-10.68695|

Here velocity is -1.94938. Do you know how is this obtained?
The average of all LOS velocities in the data above is -8.194897852. The mean on a yearly basis velocity is -2.13652694 [as resulting from: -8.194897852/3.835616438; where 3.835616438 is years (days between first and last acquisition (1400) / 365 = 3.835616438 ].
If I try to do the count on a yearly basis I get:

|YEAR|Mean Velocities|
|---|---|
|2003|-3.806063|
|2004|-5.590546556|
|2005|-13.58075025|
|2006|-7.068110783|
|2007|-10.5291|

Which clearly does not match with the velocity value of -1.94938 mm/yr.

I tried several approaches but I cannot obtain the velocity value from the LOS time series. Please, could you tell me how is the LOS velocity (mm/yr) calculated?

Thanks a lot

[ABraun]

I’m just guessing, but the average velocity could be the slope of a linear regression of all points along the investigated time rather than the mathematical mean.

[SimoneA]

Hi @ABraun , nice talking with you again. I already tried that, but it doesn’t work. The slope is -8.909038272

[eaeo]

Firstly, in your top example, where you have |date | LoS_Deformation| the los values are displacement (in mm) relative to the master date. Make sure you don’t confuse them for velocities.

To get velocity you need to know the average change in displacement over a time period.

In StaMPS the mean velocity calculation happens in ps_plot.m from line 1604 onwards: StaMPS/ps_plot.m at c159eb81b16c446e0e8fdef7dd435eb22e0240ed · dbekaert/StaMPS · GitHub

As you can see in line 1615, the velocity is calculated by fitting a straight line to displacement vs time, but the fit is weighted. The weights (named sm_cov here) are usually the standard deviation (‘noise’) estimates for each interferogram.

[alexsunny123]

@eaeo

Firstly, in your top example, where you have |date | LoS_Deformation| the los values are displacement (in mm) relative to the master date. Make sure you don’t confuse them for velocities.

To get velocity you need to know the average change in displacement over a time period.

In StaMPS the mean velocity calculation happens in ps_plot.m from line 1604 onwards

As you can see in line 1615, the velocity is calculated by fitting a straight line to displacement vs time, but the fit is weighted. The weights (named sm_cov here) are usually the standard deviation (‘noise’) estimates for each interferogram.

thanks for the awesome information.

[alexsunny123]

@alexsunny123

@eaeo

Firstly, in your top example, where you have |date | LoS_Deformation| the los values are displacement (in mm) relative to the master date. Make sure you don’t confuse them for velocities.

To get velocity you need to know the average change in displacement over a time period.

In StaMPS the mean velocity calculation happens in ps_plot.m from line 1604 onwards

As you can see in line 1615, the velocity is calculated by fitting a straight line to displacement vs time, but the fit is weighted. The weights (named sm_cov here) are usually the standard deviation (‘noise’) estimates for each interferogram. https://ometv.onl https://chatroulette.top

thanks for the awesome information.

thanks my issue has been fixed.

[mirza.waqar]

Thank you very much for this answer. I have another question, how I can get total deformation again it will be the weighted sum?

[Shadi1]

@SimoneA

Let’s take the following data obtained from a single P

Just a quick question. Would you like to share how you managed to obtain such data for a single PS point?

[Shadi1]

@eaeo

To get velocity you need to know the average change in displacement over a time period.

Much appreciated. So, is this why the velocity calculated, is referred to as the mean velocity?

And also since it’s calculated based on the average displacement over time with respect to the master scene, it means that the master scene itself will be considered to be the point of zero where displacement before and after shall be compared to, which brings up the deformation sign discussion. Will the negative sign of a displacement for a date before the master means a different Los direction of displacement from a date after the master?

[eaeo]

For total displacement you could do:

a) (mean velocity) * (number of years between first and last observation dates)
or
b) (displacement at last date) - (displacement at first date)

It will depend which one seems more appropriate for what you are aiming to study. Usually if someone says total displacement I’d assume they meant (b).